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Find the constant term in the expansion of `(2x^(4)=(1)/(3x^(7)))^(11)`

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The correct Answer is:
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`T_(r+1)=^(11)C_(r).(2x^(4))^(11-r)(-(1)/(3x^(7)))^(r)`
`=^(11)C_(r).2^(11-r).x^(44-4r).((-1)^r)/(3^(r).x^(7r))`
`=^(11)C_(r).(2^(11-r)(-1)^(r))/(3^(r)).x^(44-11r)`
Let 44- 11r =0
`rArr " "r=4`
`:.` Constant term `=^(11)C_(4).(2^(11-4)(-1)^(4))/(3^(4))`
`(|ul11)/(|ul4|ul7).(2^(7))/(3^(4))`
`=(8xx9xx10xx11)/(1xx2xx3xx4)xx(128)/(81)`
`=(14080)/(27)`
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