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Using binomial theorem, evaluate : (102)...

Using binomial theorem, evaluate : `(102)^5`

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`(102)^(5)=(100+2)^(5)`
`=^(5)C_(0)(100)^(5).(2)^(0)+^(5)C_(1)(100)^(4)(2)^(1)+^(5)C_(2)(100)^(5)(2)^(2)`
`+^(5)C_(3)(100)^(2)(2)^(3)+^(5)C_(4)(100)(2)^(4)`
`+^(5)C_(3)(100)^(2)(2)^(3)+^(5)C_(4)(100)(2)^(4)`
`+^(5)C_(5)(100)^(0)(2)^(5)`
`=^(5)C_(0)(10000000000)+^(5)C_(1)(100000000).2`
`+^(5)C_(2)(1000000).4+^(5)C_(3)(10000).8`
`+^(5)C_(4)(100)16+^(5)C_(5)(2)^(5)`
`=1.(10000000000)+5(100000000).2`
`+10(1000000).4+10(10000)8`
`+5(100)16+1(32)`
`=10000000000 +1000000000 + 40000000`
`+800000 + 8000 +32`
`=11040808032`
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