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Prove that Sigma(r=0)^(n) 3^(r)""^(n)C(r...

Prove that `Sigma_(r=0)^(n) 3^(r)""^(n)C_(r)=4^(n)`

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The correct Answer is:
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`L.H.S =overset(n)underset(r=0)(Sigma).^(n)C_(r).3^(r)=^(n)C_(0).3^(0)+^(n)C_(1).3^(1)`
`+^(n)C_(2).3^(2)+......+^(n)C_(2).3^(n)`
`=(1+3)^(n)=4^(n)=R.H.S` Hence Proved.
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