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Find the area bounded by the y-axis, y=c...

Find the area bounded by the y-axis, `y=cosx ,a n dy=sinxw h e n0lt=xlt=pi/2dot`

A

`2(sqrt(2-1))`

B

`sqrt(2)-1`

C

`sqrt(2)+1`

D

`sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

Given curves `y=sin x ` and `y-cos x` meet
wher `sin x= cos x`
and `tan x=1`
`implies x=(pi)/(4)`

` :. ` Area of required shaded region
`=int_(0)^(pi//2)(cos x-sin x)dx=[sin x+cos x]_(0)^(pi//4)`
`="sin"(pi)/(4)+"cos"(pi)/(4)-(0+1)=(1)/(sqrt(2))+(1)/(sqrt(2))-1`
`=(2)/(sqrt(2))-1=sqrt(2)-1` sq. units.
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NAGEEN PRAKASHAN-APPLICATIONS OF INTEGRALS-Miscellaneous Exercise
  1. Find the area under the given curves and given lines:(i) y=x^2,x = 1,...

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  2. Find the area between the curves y = xand y=x^2.

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  3. Find the area of the region lying in the first quadrant and bounded b...

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  4. Sketch the graph of y = |x + 3|and evaluateint-6 0|x+3|dx.

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  5. Find the area between the x-axis and the curve y=sinx from x=0 to x=2p...

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  6. Find the area enclosed between the parabola y^2=4a xand the line y = ...

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  7. Find the area enclosed by the parabola 4y=3x^2 and the line2y = 3x + ...

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  8. Find the area of the smaller region bounded by the ellipse (x^2)/9+(y...

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  9. Find the area of the smaller region bounded by the ellipse (x^2)/(a^2...

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  10. Find the area of the region enclosed by the parabola x^2=y , the li...

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  11. Using the method of integration find the area bounded by the curve |...

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  12. Find the area bounded by curves {(x ,y):ygeqx^2 and y = | x |}

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  13. Using the method of integration find the area of the triangle ABC, ...

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  14. Using the method of integration find the area of the region bounded b...

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  15. Find the area of the region {(x ,y): y^2lt=4x ,4x^2+4y^2lt=9}

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  16. The area (in square units) bounded by the curve y=x^3, the x-axis and ...

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  17. The area bounded by the curve y = x | x | , x-axis and the ordinates...

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  18. The area of the circle x^2+y^2=16 exterior to the parabola y^2=6x is

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  19. Find the area bounded by the y-axis, y=cosx ,a n dy=sinxw h e n0lt=xlt...

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