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Find th equation of the plane which is a...

Find th equation of the plane which is at distance of 8 units from origin and the perpendicular vector from origin to this plane is `(2hati+hatj-2hatk)`.

Text Solution

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The correct Answer is:
`vecr.(2hati+hatj-2hatk)=24`
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Find the equation of the plane which is at a distance of sqrt(29) units from origin and the perpendicular vector from oiring to this plane is (4hati-2hatj+3hatk) .

Find the vector and equation of a plane which is at a distance of 10 units from origin and normal vector from origin to this plane is 2hati-hatj+2hatk .

Knowledge Check

  • The cartesian equation of the plane which is at a distance of 6/sqrt29 form the origin and the normal vector from the origin is (2hati-3hatj+4hatk) is

    A
    `3x-2y+4z=3`
    B
    `2x-3y+4z=6`
    C
    `x-3y+2z=6`
    D
    None of the these

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