Home
Class 10
MATHS
Sum of the areas of two squares is 468\ ...

Sum of the areas of two squares is `468\ m^2`. If the difference of their perimeters is 24 m, find the sides of the two squares.

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the information given in the question to form equations and solve for the sides of the two squares. ### Step 1: Define the variables Let the side of the first square be \( x \) meters and the side of the second square be \( y \) meters. ### Step 2: Write the equations based on the problem statement 1. The sum of the areas of the two squares is given as: \[ ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Sum of the areas of two squares is 640m^(2). If the difference of their perimeters is 64m, find the sides of the two squares.

Sum of the areas of two squares is 260 m^(2) . If the difference of their perimeters is 24 m then find the sides of the two squares.

The sum of the areas of two squares is 640 m^(2) . If the difference in their perimeters be 64 m, find the sides of the two squares.

Sum of the areas of two squares is 544 m^(2) . If the difference of their perimeters is 32 m. find the sides of two squares.

Sum of the areas of two squares is 400cm. If the difference of their perimeters is 16cm, find the sides of the two squares.

Sum of the ares of two squares is 544 m^2 . if the difference of their perimeters is 32. find the sides of two squares.

The sum of the areas of two squares is 157 m^(2) . If the sum of their perimeters is 68 m , find the sides of the two squares .

Sum of the areas of two squares is 468m^(2). If the difference of their perimeters is 24m, formulate the quadratic equation to find the sides of the two squares.

Sum of areas of two squares is 244 cm^(2) and the difference between their perimeter is 8 cm. Find the ratio of their diagonals.