A test cross of `F_(1)` flies +a/+b produced the following offspring
`++/ab=9`
`ab//ab=9`
`+b//ab=41`
`a+//ab=41`
What will be distance between linked gene :-

A test cross of F_(1) flies +a/+b produced the followings, ++/ab(R) 9 " " ab/ab(R)9 +b/ab(R) 41 " " a+/ab(R)41 This cross represents

A test cross of F_(1) flies ++/ab produced the followings, ++/ab(R) 9 " " ab/ab(R)9 +b/ab(R) 41 " " a+/ab(R)41 This cross represents

A heterozygous individual ++ab is crossed to its revessive parent and has produced the offsprings in the following proportion. ++//ab-200 a+//ab-50 +b//ab-30 ab//ab-100 What is the expected distance between the two gene loci ?

A heterozygous individual ++ab is crossed to its revessive parent and has produced the offsprings in the following proportion. ++//ab-200 a+//ab-50 +b//ab-30 ab//ab-100 What is the expected distance between the two gene loci ?

An individual homozygous for gene a and b is cross with wild type and F_1 was back crossed with the double recessive. The appearance of the offspring is as follows ++ to 39 ab to 31 a+ to 17 +b to 13 Find out the distance between genes a and b .

An individual homozygous for gene a and b is cross with wild type and F_1 was back crossed with the double recessive. The appearance of the offspring is as follows ++ to 39 ab to 31 a+ to 17 +b to 13 Find out the distance between genes a and b .

Simplify in following. 6a - 2b - ab - (3a+ b - ab) + 2ab - b + a

Individuals homozygous for ab genes were crossed with wild type (++). The F_(1) hybrid thus produced was test crossed. It produces progeny in following proportion. Now, calculate the distance between a and b genes.