A cell of two volt and 1.5 ohm internal resistance is connected to two ends of a 100 metre wire. The resistance of wire is `0.005 ohm//m`. The potential gradient of the wire is

A cell of emf 2Vand internal resistance 1.5Omega is connected to two ends of 100 cm wire. The resistance of the wire is 0.005 Omega//cm. The potential gradient of the wire is

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.

A cell of emf 2 volt and internal resistance 1.5Omega is connected to the ends of 1 long wire. The resistance of wire is (0.5Omega)/(m) . Find the value of potential gradient on the wire.

A cell of internal resistance 3 ohm and emf 10 volt is connected to a uniform wire of length 500 cm and resistance 3 ohm . The potential gradient in the wire is

A battery of emf 26V and internal resistance 0.4 ohm is connected to a resistance of 10ohm and a potentiometer wire of length 10m. What is the potential gradient on the wire if the resistance of the potentiometer wire is 5 ohm –

A cell of e.m.f. 2 V and negligible internal resistance is connected to a potentiometer wire of resistance 10 Omega and length 4 m. The potential difference per unit length (potential gradient ) of the wire is

A cell of e.m.f. 2 V and negligible internal resistance is connected to a potentiometer wire of resistance 10 Omega and length 4 m. The potential difference per unit length (potential gradient ) of the wire is

The resistance of 10 metre long potentiometer wire is 1 ohm/meter . A cell of e.m.f. 2.2 volts and a high resistance box are connected in series to this wire. The value of resistance taken from resistance box for getting potential gradient of 2.2 millivolt/metre will be

A cell of e.m.f. 2 volt and negligible internal resistance is connected to potentiometer wire of length 4 m and resistance 25 Omega , to form a closed circuit. Find the potential gradient along the wire .