If `a_n=3/4-(3/4)^2+(3/4)^3+...(-1)^(n-1)(3/4)^n` and `b_n=1-a_n`, then find the minimum natural number n, such that `b_n>a_n`

If quad a_(n)=(3)/(4)-((3)/(4))^(2)+((3)/(4))^(3)+...(-1)^(n-1)((3)/(4)) and b_(n)=1-a_(n), then find the minimum natural number n,such that b_(n)>a_(n)

Let A_n=(3/4)-(3/4)^2+(3/4)^3+….+(-1)^(n-1)(3/4)^n and B_n = 1-A_n . find the least odd natural numbers n_0 , so that B_ngtA_n A for all ngen_0

Complete the following statements. and b_n=1-1_n then the smallest natural number n_0 , such that b_n > a_n !V n> n_0 is

1^(3)+2^(3)+3^(3)+.....+n^(3)=(n(n+1)^(2))/(4), n in N

1+5+9+...+(4n-3)=n(2n-1) for all natural numbers n

In an AP, given a_n=4, d=2, S_n=-14 find n and a

sum_(n=1)^(oo)((1)/(4n-3)-(1)/(4n-1))=(pi)/(n) find n