The triple points of `Ne` and `CO_(2)` are 24.57K and 216.55K respectively. Express these temperatures in the Celsius and Fahrenheit scales.

Explanation

t=T-273
(i) `t=24.57-273" "i.e.,24.57K=-248.43^(@)C`
(ii) `t=216.55K=-56.45^(@)C" ""We know that "C=(5)/(9)(F-32)`
i.e. `F=(9C)/(5)+32`
(i) `F=(9)/(5)(-248.43)+32=-415.17" "i.e.-248.43^(@)C=-415.17^(@)F`
(ii) `F=(9)/(5)(-56.45)+32=-69.61" "i.e.-56.45^(@)C=-69.61^(@)F`