A geyser heats water flowing at the rate of 3.0 litres per minute from `27^(@)` to `77^(@)C`. If the geyser operates on a gas burner, what is the rate to consumption of the fuel if its heat of combustion is `4.0xx10^(4)J//g?`

Explanation

Given, `(V)/(t)=(3xx10^(-3))/(60)=5xx10^(-5)m^(3)//s`
`theta_(2)-theta_(1)=77-27=50^(@)C" "(m)/(t)=?" "(H)/(t)=(mstheta)/(t)`
where `(V)/(t)=5xx10^(-5)" "i.e.(m)/(rhot)=5xx10^(-5)`
or `(m)/(t)=5xx10^(-5)xx10^(3)=5xx10^(-2)kg//s`
Hence `(H)/(T)=5xx10^(-2)xx4200xx(77-27)=10500Js^(-1)`
Mass of fuel per unit time `=(10500)/(4xx10^(7))=0.260kgs^(-1)=15.6kg" min"^(-1)`