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The volume of 1 kg water is reduced by 9...

The volume of 1 kg water is reduced by `91cm^(3)` on melting. Calculate the change in the internal energy when 2 kg ice melts at NTP.

Text Solution

Verified by Experts

We know that `Q=mL=2xx3.36xx10^(5)J`
i.e. `Q=6.72xx10^(5)J`
Decrease in volume of 2 kg of ice `=2xx91cm^(3)=-182xx10^(5)J`.
Work done `W=PDeltaV=(1xx10^(5))(-182xx10^(-6))=-18.2J`
But from the I law of thermodynamics
`DeltaU=Q-W`
`=6.72xx10^(5)-(18.2)=6.7202xx10^(5)J`.
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