Calculate the amount of work done in taking the gas from the state (i) P to Q (ii) Q to R (iii) R to P (iv) the entire cycle,

Explanation

(i) Work done from P to Q : `V_(2)-V_(1)=(5-25)=-20 m^(3)`
`W=P(V_(2)-V_(3))=-5xx20=- -100 J`
(ii) Work done from Q to R = Area `QRMNQ=(1)/(2) (QP)(RP)+(MN)(PM)`
`=(1)/(2)(20)(15)+(20xx5)=+250J`
(iii) Work deon from R to P
`Delta V=0` hence `W = P Delta V=0`
(iv) Work done uring one cycle `=(1)/(2) bh=(1)/(2)xx QPxxRP=(1)/(2)xx20xx15=150J`