The ratio of specific heats of a gas in `1.40`. There are 200 moles of gas initially present. The gas undergoes adiabatic expansion and as a result which, the temperature of the gas falls from 400 K to 100 K. Give `R=8.312J "mole"^(-1) K^(-1)`. Calculate the amount or work done by the gas on the surroundings.

Explanation

Given `n=200,R=8.312 T_(e)=400K, T_(2)=100K`
`T_(1)-T_(2)=300 K, gamma=1.4`
We know, `W=(muR)/(gamma-1)(T_(1)-T_(2))=(200xx8.312xx300)/(0.4)=1.26xx10^(6)J`