The working substance in a Carnot's heat engine absorbs `5xx10^(6)J` of heat from the source and reject `2xx10^(6)J` of heat of the sink. Calculate the (i) heat converted into work and (ii) efficiency of the engine.

Explanation

`Q_(1)=5xx10^(6)J " " Q_(2)=2xx10^(6)J`
Work done `=Q_(1)-Q_(2)=(5-2)xx10^(6)J=3xx10^(6)J`.
Efficiency of the engine `eta=(W)/(Q_(1)) " " i..e, eta =(3xx10^(6))/(5xx10^(6))=0.6 or 60%`