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Caclulate the change in entropy of a 100...

Caclulate the change in entropy of a 1000 kg of water converted into steam. Latent heat of steam `=2.268xx10^(6)Jkg^(-1)`

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We know that `ds=(dQ)/(T),T=373K`
Here `dQ=mL=(1000)(2.268xx10^(6))`
`dQ=2.268xx10^(9)J`.
`:. dS=(2.268xx10^(4))/(373)=6.08xx10^(6)Jkg^(-1)`
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