A Carnot heat engine absorbs 600J of heat from source of temperature 800K and rejects 300J of heat to the sink. Calculate efficiency and temperature of the sink.

Explanation

`Q_(1)=600, T_(1)=800K, Q_(2)=300J, eta=?`
Using `(Q_(1))/(Q_(2))=(T_(1))/(T_(2))`
we ge4t, `T_(2)=(Q_(2))/(Q_(1)).T_(1)=(300)/(600)xx800K`
`:. T_(2)=400K`
By using `eta=1-(T_(2))/(T_(1))` we get,
`eta=1-(400)/(800) =0.5`
i.e., efficiency of Carnot.s heat engine is `50%`.