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Give the expression for the potential en...

Give the expression for the potential energy of a particle executing SHM.

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`P.E.=U=(1)/(2)kx^(2)` for oscillation along .x. direction and .k. is force constant and `k=momega^(2)` i.e., `U=(1)/(2) omega^(2)(A^(2)cos^(2)(omegat+phi)).`
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Knowledge Check

  • The total energy of a particle, executing S.H.M. is :

    A
    `prop X`
    B
    `prop X^(1//2)`
    C
    independent of X
    D
    `prop X^(2)` where X is the displacement from the mean position

  • The ratio of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude, the distance being measured from its equilibrium position is

    A
    `4:1`
    B
    `8:1`
    C
    `3:1`
    D
    `2:1`

  • The ratio of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude, the distance being measured from its equilibrium position is :

    A
    `4:1`
    B
    `8:1`
    C
    `3:1`
    D
    `2:1`

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