Calculate the time taken for particele energy to drop to half its initial value in the case of a damped oscillator.

Explanation

We know that `E(t)=E(0)e^(-bt//m)` where`" "E(0)=(1)/(2)kA^(2)`
`"Given, "E(t)=(1)/(2)(E(0))," "therefore " "(1)/(2)=e^(-bt//m)=e^((1)/(bt//m))`
`"i.e. "e^(bt//m)=2" "(bt)/(m)=2.303log 2=0.693`
`t=(0.693m)/(b)`