Two spring of spring constants `10Nm^(-1) and 20 Nm^(-1)` are connected in series. One end of the combination is supported rigidly and the other to a body of mass 2 kg. Neglecting the masses of the springs, calculate the frequency of oscillation of the system.

Explanation

`k_(1)=10Nm^(-1), k_(2)=20Nm^(1), m=2kg`
For series combination
`k=(k_(1)k_(2))/(k_(1)+k_(2))` so that
`k=(10xx20)/(30)=(20)/(3)=6.67Nm^(-1)`
We know that `f=(1)/(2pi)sqrt((k)/(m))=(1)/(2xx3.142)xxsqrt((6.67)/(2))`
`f=0.291Hz.`