Calculate the period of oscillation of a body falling freely inside the tunnel created along the diameter of the earth. Given average density of the material of the Earth `5500kgm^(-3)` and universal gravitational constant `6.67xx10^(-11)Nm^(2)kg^(-2)`.

Explanation

We know that time period of oscillation of a body dropped in the tunnel,
`T=sqrt((3pi)/(Grho))`
`"i.e. "T=sqrt((3xx3.142)/(6.67xx10^(-11)xx5500))=sqrt((0.2567)/(10^(-8)))=0.5069xx10^(4)s=5069s`
`T="1 hr 24 min 29 sec"`