Plot the corresponding SHM of particle. Indicate the intial `(t=0)` position of the particle, the radius of the circle and angular speed of the rotating particle. Consider sense of rotation to be anticlockwise and x in cm and t is in s.
(b) `x=cos((pi)/(6)-t)`

Explanation

`x=cos ((pi)/(6)-t)=1.cos [-(t-(pi)/(6))]=1.cos(t-(pi)/(6)).`
`or x = cos (1.t-(pi)/(6))=cos(t+(11pi)/(6)).`
Comparing this with `x=A cos (omegat+phi)` we get,
`A=1cm, omega="1 rad s"^(1), phi=-(pi)/(6)" rad "{:("2pi-(pi)/(6)),((=11pi)/(6)):}`