Given displacement of a particle executing SHM `y(t)=A cos (omegat+phi)`. Plot instantaneous displacement, velocity and acceleration of particle with respect to time.

If the displacement of a particle is given by y(t)=A sin (omega t +phi) , then find the maximum velocity of the particle.

The displacement time graph of a particle executing SHM is as shown in the figure. The corresponding force-time graph of the particle is-

The displacement equation of a particle executing S.H.M is given by y=0.01 sin pi(t+0.005)m . Calculate the maximum velocity and displacement at the time of start of the motion.

The displacement of a particle is represented by following equation: s=3t^(3) +7t^(2) +5t +8 where is in metre and in second the acceleration of particle at s is

If the displacement of a particle is givne by s=((1)/(2)t^(2)+4sqrtt)m . Find the velocity and acceleration at t = 4 seconds.

A particle executing S.H.M. has an amplitude of I m and time period 2 s. The velocity when displacement being 0.5 m is

A particle moves in a straight line such that its displacement is s^(2)=t^(2)+1 Find. (ii) acceleration as a function of 's'

The displacement of a particle is given by x=(t-2)^(2) where x is in meters and in seconds. The distance covered by the particle in first 4 seconds is :