For the dissociation reaction `N_(2)O_($) (g)hArr 2NO_(2)(g)`, the degree of dissociation `(alpha)`interms of `K_(p)` and total equilibrium pressure P is:

For the dissociation reaction N_(2)O_(4) (g)hArr 2NO_(2)(g) , the degree of dissociation (alpha) interms of K_(p) and total equilibrium pressure P is:

For the reaction, N_(2)O_(4)(g)hArr 2NO_(2)(g) the reaction connecting the degree of dissociation (alpha) of N_(2)O_(4)(g) with eqilibrium constant K_(p) is where P_(tau) is the total equilibrium pressure.

For the reaction, N_(2)O_(4)(g)hArr 2NO_(2)(g) the reaction connecting the degree of dissociation (alpha) of N_(2)O_(4)(g) with eqilibrium constant K_(p) is where P_(tau) is the total equilibrium pressure.

For the reaction, N_(2)O_(4)(g)hArr 2NO_(2)(g) the degree of dissociation at equilibrium is 0.l4 at a pressure of 1 atm. The value of K_(p) is

For the reaction, N_(2)O_(4)(g)hArr 2NO_(2)(g) the degree of dissociation at equilibrium is 0.14 at a pressure of 1 atm. The value of K_(p) is

For the dissociation reaction N_(2)O_(4)(g)hArr2NO_(2)(g), the equilibrium constant K_(P) is 0.120 atm at 298 K and total pressure of system is 2 atm. Calculate the degree of dissociation of N_(2)O_(4) .

In the dissociation of PCl_(5) as PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation is alpha at equilibrium pressure P, then the equilibrium constant for the reaction is

In the dissociation of PCl_(5) as PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation is alpha at equilibrium pressure P, then the equilibrium constant for the reaction is

For the reaction N_(2)O_(4)(g) hArr 2NO_(2)(g) the degree of dissociation at equilibrium is 0.2 at 1 atmospheric pressure. The equilibrium constant K_(p) will be

For the reaction N_(2)O_(4)(g)hArr2NO_(2)(g) , the degree of dissociation at equilibrium is 0.2 at 1 atm pressure. The equilibrium constant K_(p) will be