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A conductor of length 3m moving in a uni...

A conductor of length 3m moving in a uniform magnetic field of strength 100 T. It covers a distance of 70 m in 5 sec. Its plane of motion makes an angle of `30^(@)` with direction of magnetic field. Calculate the emf induced in it.

Text Solution

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Given : ` 3m , B = 100 T, V = 70/5 = 14 ms^(-1) , theta = 30^(@)`
We know that , induced emf = ` e = BLv sin theta `
` i.e, e = 100 xx 3 x 15 xx sin30^(@)`
` i.e, e = ( 100 xx 42 xx 1)/2`
` therefore e = 2100 V `
Induced emf between the ends of the conductor = 2100 V .
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