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A small telescope has an objective lens of focal length 144cm and an eyepiece of focal length 6.0cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

Text Solution

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Given : `f_(0)=144 cm, f_(e)=6.0 cm`.
Magnifying power of the telescope
`m=f_(0)//f_(e)=(144)/(6)=24`
Separation between objective and eye piece
`=|f_(0)+f|`
`=144+6`
`=150cm`
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