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The current in a coil of 20 mH changes f...

The current in a coil of 20 mH changes from 2.5 A to 3A to in `1/(100)` second. Find the induced emf.

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Given : `L=20 mH =2xx10^(-2)H,dI =I_2-I_1=3-2.5=0.5 A, dt = 1/(100) s=10^(-2)s, e= ?`
Magnitude of induced emf is `e=L(dI)/(dt)=(20xx10^(-2)xx0.5)/(10^(-2))=1V`.
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