Current in a coil changes from 4A to 0A in 0.1 s. If the average emf induced is 100 volts, what is the self inductance of the coil ?

Explanation

Self inductance of a coil is given by `E=(LdI)/(dt)`
`E= (LdI)/(dt) =100=L 4/(0.1)`
`therefore L= (100xx0.1)/4=2.5`
`therefore` Self inductance of the coil is 2.5 henry.