Calculate the equivalent inductance between A and B from the following circuit.

Explanation

Using `L_P =(L_1L_2)/(L_1+L_2)`
We get , `L_p=(2xx2)/(2+)=4//4=1H`
`therefore L_s=sumL=(1+1+3)H=5H`
`L_p^1=(5xx6)/(5+6)=(30)/(11)H`
i.e., `L_p^1 =2.73 H`
Hence, `L_(AB)=2.73 H`