Find the value of `a` if the curves `(x^2)/(a^2)+(y^2)/4=1a n dy^3=16 x` cut orthogonally.

For what values of a will the curves (x^(2))/(a^(2))+(y^(2))/(4)=1 and y^(3)=16x intersect at right angles?

The number of values of a for which the curves 4x^(2)+a^(2)y^(2)=4a^(2) and y^(2)=16x are orthogonal is

The number of values of 'a' for which the curves y^(2)=3x^(2)+a and y^(2)=4x intersects orthogonally

Prove that the curve 2x^(2)+3y^(2)=1 and x^(2)-y^(2)=(1)/(12) intersect orthogonally.

Find the condition for the curve (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 and xy =c^(2) to interest orthogonally.

Show that the circles x^(2)+y^(2)-6x+4y+4=0and x^(2)+y^(2)+x+4y+1=0 cut orthogonally.

Find the area bounded by the curve 4y^(2)=9x and 3x^(2)=16y

If the curves y^(2)=4x and xy=a,a>0 cut orthogonally,then a is

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =