(dy)/(dx)+1=cosec x(x+y)

The solution of differential edquation (dy)/(dx) +1 = cosec (x+y) is

The general solution of the differential equation (dy)/(dx)+1="cosec"(x+y) is -

Find the particular solution of the differential equation x(dy)/(dx)=y+x cosec ((y)/(x))=0; given that y=0 when x=1

Solve: (dy)/(dx)-y/x + cosec (y/x) =0, given y = 0 when x = 1

Solution of the differential equation 1+(dy)/(dx)+cosec(x+y)=0 is

Solve the following differential equation: (dy )/(dx) =x^3 cosec y given that y(0 ) =0 .

(dy)/(dx) - (y)/(x) + cosec ((y)/(x)) = 0, y = 0 when x = 1.

(dy)/(dx) - (y)/(x) + cosec ((y)/(x)) = 0, y = 0 when x = 1.

solve (dy)/(dx)-y/x+cosec(y/x)=0 y=0 when x=1