" 5) "cos y(dy)/(dx)=e^(x);y=(pi)/(2)" when "x=0

Solve the following initial value problem: cos y(dy)/(dx)=e^(x),y(0)=(pi)/(2)

(dy)/(dx)=2e^(x)y^(3) , when x=0, y=(1)/(2)

(dy)/(dx) -y =e^(x ) " when" x=0 and y=1

cos ((dy)/(dx)) = a (a ne R), y = 2 when x = 0

(1+e^(x))/(y)(dy)/(dx)=e^(x), when y=1, x=0

If y=e^(sin x) ,the value of (dy)/(dx) at x=(pi)/(2) is

The solution of the differential equation (1+e^(x))y(dy)/(dx) = e^(x) when y=1 and x = 0 is

If y=y(x) is the solution of the equation e^(sin y) cos y""(dy)/(dx) +e^(sin y) cos x = cos x,y (0)=0, then 1+y ((pi)/(6)) +( sqrt(3))/(2) y((pi)/(3)) +(1)/( sqrt(2)) y((pi)/(4)) is equal to

If xsin((y)/(x))dy = (y sin((y)/(x))-x)dx and y(1) = (pi)/(2) then the value of cos((y)/(e^(7))) is __________.