" (iii) "23.3408

If 213xx16=3408, then 1.6xx21.3 is equal to ( a) 0.3408 (b) 3.408 (c) 34.08 (d) 340.8

23/4

Find the remainder when (17)^(23) + (29)^(23) is divided by 23.

If the mode of 22 ,\ 21 ,\ 23 ,\ 24 ,\ 21 ,\ 20 ,\ 23 ,\ 26 ,\ x and 26 is 23, then x= (a) 20 (b) 21 (c) 23 (d) 24

(0.00625backslash of backslash(23)/(5)) when expressed as a vulgar fraction,equals (a) (23)/(80) (b) (23)/(800) (c) (23)/(8000) (d) (125)/(23)

Find the product : 2.3 xx0.23xx0.1

The value of cot(sum_(n=1)^23 cot^-1(1+sum_(k=1)^n 2k)) is (a) 23/25 (b) 25/23 (c) 23/24 (d) 25/26