Find the length of normal to the curve `x=a(theta+sintheta),y=a(1-costheta)` at `theta=pi/2dot`

The length of normal to the curve x=a(theta+sin theta), y=a(1-cos theta), at theta=(pi)/(2) is

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

Find the slopes of the tangent and the normal to the curve x=a(theta-sintheta),\ \ y=a(1-costheta) at theta=pi//2

Find the slopes of the tangent and the normal to the curve x=a(theta-sintheta) , y=a(1+costheta) at theta=-pi//2

Find the equations of the tangent and the normal to the curve x=a(theta+sintheta),\ \ y=a(1-costheta) at theta at indicated points.

Find the equations of the tangent and the normal to the curve x=theta+sintheta , y=1+costheta at theta=pi//2 at indicated points.

Find the slope of the normal to the curve x=1-asintheta , y=b\ cos^2theta at theta=pi/2 .