Distance between the genes a,b,c and d in map units is a-d =3.5 , b-c=1,a-b=6, c-d=1.5 and a-c=5 .Find out the sequecne of the genes

The distance between the genes a,b,c and d in mapping units are a-d=3.5 , b-c=1,a-b=6,c-d=1.5,a-c=5 Find out the sequence of arrangement of these genes:

The distance between the genes a,b,c and d in mapping units are a-d=3,5, b-c=1,a-b=6,c-d=1.5, a-c=5. Find out the sequence of arrangeent of these genes

The distance between the genes a, b, c, d in mapping units are a - d = 3cdot5 , b - c = 1 , a - b = 6 , c - d = 1 cdot 5 , a - c = 5 Find out the sequence of arrangement of these genes

the map distance between gennes A and B is 3 units ,between B and C 10 units and between C and A 7 units .what is the sepuence of the genes on the linklage map ?

The map distance between genes A and B is 3 units, between B and C 10 units and between C and 7 units. The order of the genes in the linkage map constructed in the above data would perhapes be

If gene freuency between genes a and c 2%, b and c 13%, b and d 4%, a and b 15%, c and d 19%. What will be the sequence of these genes in a chromosome?

If gene freuency between genes a and c 2%, b and c 13%, b and d 4%, a and b 15%, c and d 19%. What will be the sequence of these genes in a chromosome?

The map distance between genes A and B is 3 units, between B and C is 10 units and between C and A is 7 units, what is the order of genes on linkage map?

The map distance between genes A and B is 3 units, between B and C is 10 units and between C and A is 7 units. Which of the following shows the correct order of the genes in a linkage map on the above data ?