Find the number of possible natural frequencies of an air column in a pipe whose frequencies lie below 1250 Hz. The length of the pipe is 85 cm. The speed of sound is `340 ms^(-1)`. Consider the two cases: (a) the pipe is closed at one end and (b) the pipe is open at both ends.

Find the number of possible natural oscillations of air column in a pipe whose frequencies lie below 1250 Hz . The length of the pipe is 85 cm . The velocity of sound is 340m*s^(-1) . Consider the following two cases: The pipe is opened from both ends

Find the number of possible natural oscillations of air column in a pipe whose frequencies lie below f_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases the pipe is closed from one end .

Find the number of possible natural oscillations of air column in a pipe whose frequencies lie below f_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases the pipe is closed from one end .

Find the number of possible natural oscillations of air column in a pipe frequencies of which lie below v_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases i. the pipe is closed from the end , ii. the pipe is open from both ends.

The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (velocity of sound = 340 ms^-1 )