If the curves `a y+x^2=7a n dx^3=y` cut orthogonally at `(1,1)` , then find the value `adot`

If the curves ay + x^(2) =7 and x^(3) =y cut orthogonally at (1,1) then the value of a is

If the curve a y+x^2=7 and x^3=y cut orthogonally at (1,\ 1) , then a is equal to (a) 1 (b) -6 (c) 6 (d) 0

If the curves y^(2)=4x and xy=a,a>0 cut orthogonally,then a is

If the curves ay+x^(2)=7 and x^(3)=y cut orthogonally at (1,1) then a=(A)1(B)-6 (C) 6(D)(1)/(6)

The curves x=y^(2) and xy =a^(3) cut orthogonally at a point, then a =

Show that x^2=y and x^3+6y=7 intersect orthogonally at (1,\ 1)

If the curve ax^(2) + 3y^(2) = 1 and 2x^2 + 6y^2 = 1 cut each other orthogonally then the value of 2a :

If (x+1,1)=(3,y-2), find the value of x and y.

The two curves x=y^2a n dx y=a^3 cut orthogonally, then a^2 is equal to a.1/3 b. 3 c. 2 d. 1//2

If curve x^(2)=9a(9-y) and x^(2)=a(y+1) intersect orthogonally then value of 'a' is