Solve `1/(a+b+x)=1/a+1/b+1/x`,`a+b !=0`

Solve: 1/(a+b+x) = 1/a+1/b+1/x,x!=0,-(a+b)

Solve the following quadratic equation by the method of factorisation:(xx) 1/(a+b+x)=1/a+1/b+1/x,a+b!=0

Solve : 1/(a+b+x)=1/a+1/b+1/x[ x ne 0, -(a+b)]

Solve the following quadratic equations by factorization method: 1/(a+b+x)=1/a+1/b+1/x ,\ \ a+b!=0

Solve for x. (1)/(a+b+x)=1/a+1/b+1/x ( Where a!=0, b!=0, x!=0, x!=-a, -b ) OR The diagonal of a rectangular field is 60m more than the shorter side. If the larger side is 30m more than the shorter side, find the sides of the field.

Solve for x . 1/(a+b+x) =(1/a + 1/b + 1/x) (Where a ne 0, b ne 0 , x ne 0 , x ne -(a+b)

Solve : 1/x - 1/(x+b)= 1/a -1/(a+b)[ x ne 0, -b]

Solve: 1/x-1/(x+b)=1/a-1/(a+b) (x!=0,-b) .

Solve for: 1/(2a+b+2x)=1/(2a)+1/b+1/(2x)

Answer any one : 1/a+b+x = 1/a+1/b+1/x, [x ne 0, - (a + b)]