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[" vi) "cos theta+sin(270^(@)+theta)-sin...

[" vi) "cos theta+sin(270^(@)+theta)-sin(270^(@)-theta)],[+cos(180^(@)+theta)=0]

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Prove that cos theta+ sin (270^@-theta)- sin (270^@-theta)+ cos (180^@+theta)=0 .

Prove the following: costheta+sin(270^@+theta)-sin(270^@-theta)+cos(180^@+theta)=0

Prove that cos theta + "sin " (270^(@) +theta) - "sin "(270^(@) -theta) + "cos " (180^(@) +theta) =0

sin(270^(@)-theta).sin(90^(@)-theta)-cos(270^(@)-theta).cos(90^(@)+theta)=

Prove that sin (270^(@)-theta) sin (90^(@)-theta)-cos(270^(@)-theta) cos (90^(@)+theta)+1=0

cos A + sin(270^(@) +A)-sin(270^(@)-A)+ cos(180^(@)-A)=

cos(270^@-theta) =

The value of cos (270^(@) + theta) cos ( 90^(@) -theta) -sin (270^(@) - theta) cos theta is

The value of cos (270^(@) + theta) cos ( 90^(@) -theta) -sin (270^(@) - theta) cos theta is