`(1) y = ae^(4x) -be^(-3x) +c (2) xy = ae^(5x) +be^(-5x)`

y = ae^(3x) + be^(-2x)

y = ae^(3x) + be^(-2x)

y = ae^(3x) + be^(-2x)

xy =Ae^(x) + Be^(-x)

(1)/(ae^(x)+be^(-x))

Form the differential equations by elimniating the arbitary constants from the following equations : (1) y =c^(2)+c/x (2) x^(3) +y^(3) = 4ax (3) y = Ae^(5x) + Be^(-5x) (4) y = A cos alpha x + B sin alpha x

If xy = ae ^(x) + be^(-x) then xy _(2) + 2y _(1) - xy =

If y=ae^(x)+be^(-x)+c," then "y'''=