" 26."tan2A=(sec2A+1)sqrt(sec^(2)alpha-1)

tan2A=(see2A+1)sqrt(sec^(2)A-1)

tan 2 A = (sec 2 A +1 ) sqrt ( (sec ^(2) A -1)) , A belongs to I or IV Quad.

tan^(-1)sqrt(3)-sec^(-1)(-2)

Show that tan 15^@+ tan 75^@ = (sec^2 15^@)/sqrt(sec^2 15^@-1)

1+tan A tan2A=sec2A

tan^(-1)(sqrt(3))+sec^(-1)(-2) =

Prove that, (sec 8 alpha -1)/(sec 4 alpha-1)= (tan 8 alpha)/(tan 2 alpha

If (sec^(4)alpha)/(sec^(2)beta)-(tan^(4)alpha)/(tan^(2)beta)=1 where alpha,betane(pi)/(2) , then find the value of (sec^(4)beta)/(sec^(2)alpha)-(tan^(4)beta)/(tan^(2)alpha)

(1+sec 2 theta)*sqrt(sec^(2) theta-1)= A) 2 sec theta B) sec 2 theta C) 2 tan theta D) tan 2 theta

Prove that tan20^(@)+tan70^(@)=(sec^(2)20^(@))/(sqrt(sec^(2)20^(@)-1))