[" TRIGONOMETRY for JEE -QUICK REVISION "],[" Q9.The expression "(tan A)/(1-cot A)+(cot A)/(1-tan A)" con be written as "]

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The expression (tan A)/(1- cot A) + ( cot A )/( 1- tan A) can be written as

Find (tan A)/((1-cot A))+(cot A)/((1-tan A))

Prove that : (tan A)/ (1 - cot A) + (cot A)/ (1 - tan A) = sec A cosec A + 1

1/(tan3A-tan A)-1/(cot 3A-cot A)=

tan^(-1) (cot x) +cot^(-1)(tan x) =

tan^(-1)(cot x)+cot^(-1)(tan x)