" 21."(s-a)tan(A)/(2)=(s-b)tan(B)/(2)=(s-c)tan(C)/(2)

Prove that (s-a)tan((A)/(2))=(s-b)tan((B)/(2))=(s-c)tan((C)/(2))

In DeltaABC , Prove that (s-a) tan (A/2)=(s-b) tan (B/2)=(s-c) tan (C/2)

s^(2)tan((A)/(2))tan((B)/(2))tan((C)/(2))

1-tan(A)/(2)tan(B)/(2)=(2c)/(a+b+c)

(viii) (b+c-a) tan( A/2) = (c+a-b) tan( B/2) = (a+b-c) tan C/2

In any Delta ABC, prove that : ((a-b)/(c))=(tan((A)/(2))-tan((B)/(2)))/(tan((A)/(2))+tan((B)/(2)))

If A+B+C=pi , then tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))+tan((C)/(2))tan((A)/(2)) is equal to a) (pi)/(6) b)3 c)2 d)1

In Delta ABC if tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))=(2)/(3) then a+c

In Delta ABC , if x=tan((B-C)/(2))tan.(A)/(2),y=tan((C-A)/(2))tan.(B)/(2) and z=tan((A-B)/(2))tan.(C)/(2) then (x+y+z)= .

In /_ABC with usual notations,if a,b,c are in A.P.then the numerical value of tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2)) is