`CH_2=CH-CH_2-CH_3overset(NBS)to B+C`
write structure of B and C.

CH_2 = undersetoverset(|)(Me)(C ) -CH_2CH_2CH_3 overset(IBr)(to) The structure of the product is

CH_3-CH_2-C≡C-CH_2-CH_3 : Write the structure of any two isomers of this compound.

An organic compound on reaction with O_3 followed by Zn and H_2O gives CH_3 - overset(O)overset(||)C-CH_2 - CH_2 - overset(O)overset(||)C-CH_3 . The structures are :

CH_(3)CH_(2)CH=CH_(2) overset(NBs)to X overset(alc. KOH)to Y . The compound Y is

Ph-CH_(2)-CH_(2)-C-=C-CH_(3)overset(Na//NH_(3))to A overset(Cl_(2)//hv)to B Identify B

CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH_(2)+HBr to A The structure of A is:

The final product ‘B’ in the following sequence of reaction is : H_(3) C - CH = CH_(2) overset(NBS)to A overset(aq.NaOH)to B