In fig two equal positive point charge `q_(1)=q_(2)=2.0mu C`. Interact with a third point charge `Q=4.0 mu C`. The magnitude as well as direction of the net force on Q is

In Fig., the three particles are fixed in place and have charges q_(1) = q_(2) = +5e and q_(3) = +2e . Distance a = 3.00 mu m . What are the (a) magnitude and (b) direction of the net electric field at point P due to the particles ?

A positive point charge q_(1) is placed at (a,0) and another positive point charge q_(2) is placed at (0,a) . Find the force acting on q_(1) .

A positive point charge q_(1) is placed at (a,0) and another positive point charge q_(2) is placed at (0,a) . Find the force acting on q_(1) .

The force of interaction between two charges q_(1)=6 mu C and q_(2)=2 mu C is 12N .If charge q=-2 mu C is added to each of the charges,then the new force of interaction is

Three point charges are arranged along X-axis. Charge q_1 =+3 muC is at origin, charge q_2 =- 5 muC is at x = 0.2 m and charge q_3 =- 8 muC . Then, where is q _3 located, if the net force on q _1 is 7 N in the negative x-direction?

Find the force on a charge q_(1)(=20 mu C) due to the charge of q_(2)(=10 mu C) if the positions of the charges are given as P_(1)(1,-1,2) and Q(-1,1,1)

Find the force on a charge q_(1)(=20 mu C) due to the charge of q_(2)(=10 mu C) if the positions of the charges are given as P_(1)(1,-1,2) and Q(-1,1,1) . .

A point charge q_(A)=+100 mu c is placed at point A (1, 0, 2) m and another point charge q_(B)=+200 mu c is placed at point B (4, 4, 2) m. Find : (i) Magnitude of electrostatic interaction force acting between them (ii) Find vec(F)_(A) (force on A due to B) and vec(F)_(B) (force on due to A) in vector form