A particle moves on the xy-pane such that its position vector is given by `vec(r)=3t^(2) hati-t^(3) hatj`. The equation of trajectory of the particle is given by

The position of a particle is given as vecr=at hati+bt^(2)hatj Find the equation of trajectory of the particle.

A particle move in x-y plane such that its position vector varies with time as vec r=(2 sin 3t)hat j+2 (1-cos 3 t) hat j . Find the equation of the trajectory of the particle.

A particle move in x-y plane such that its position vector varies with time as vec r=(2 sin 3t)hat j+2 (1-cos 3 t) hat j . Find the equation of the trajectory of the particle.

The position vector of a particle vecr =(t^2-1)hati +2thatj . Determine the trajectory of the particle in the xy plane.

A particle moves in space such that its position vector varies as vec(r)=2thati+3t^(2)hatj . If mass of particle is 2 kg then angular momentum of particle about origin at t=2 sec is

A particle moves in space such that its position vector varies as vec(r)=2thati+3t^(2)hatj . If mass of particle is 2 kg then angular momentum of particle about origin at t=2 sec is

The position vector of the particle is vecr=3t^2 hati+5t hatj+9hatk . What is the acceleration of the particle?

A particle moves in xy-plane. The position vector of particle at any time is vecr={(2t)hati+(2t^(2))hatj}m. The rate of change of theta at time t = 2 second. ( where 0 is the angle which its velocity vector makes with positive x-axis) is :

The position vector of a particle moving in x-y plane is given by vec(r)=(t^(2)-4)hat(i)+(t-4)hat(j) . Find (a) Equation of trajectory of the particle (b)Time when it crosses x-axis and y-axis