If `f:[-5,5]rarrR` is differentiable function and if`f^(prime)(x)` does not vanish anywhere, then prove that `f(-5)!=f(5)dot`

If fquad :quad [quad -5,quad 5]rArr R is a differentiable function and if f'(x) does not vanish anywhere,then prove that f(-5)!=f(5)

If f:[-5,5]rarr R is differentiable and if f'(x) doesnt vanish anywhere,then prove that f(-5)!=f(5)

If f is continuously differentiable function then int_(0)^(1.5) [x^2] f'(x) dx is

If f(x) is a twice differentiable function and given that f(1)=2,f(2)=5 and f(3)=10 then

If f:R rarrR is a function, then f is

If f is continuously differentiable function then int_(0)^(2.5) [x^2] f'(x) dx is equal to

Let f(x) is a differentiable function on x in R , such that f(x+y)=f(x)f(y) for all x, y in R where f(0) ne 0 . If f(5)=10, f'(0)=0 , then the value of f'(5) is equal to

Let y=f(x) be a differentiable function such that f(-1)=2,f(2)=-1 and f(5)=3 then the equation f'(x)=2f(x) has

Let f : (-5,5)rarrR be a differentiable function of with f(4) = 1, f'(4)=1, f(0) = -1 and f'(0) = If g(x)=(f(2f^(2)(x)+2))^(2), then g'(0) equals

Let f : (-5,5)rarrR be a differentiable function of with f(4) = 1, f'(4)=1, f(0) = -1 and f'(0) = If g(x)=(f(2f^(2)(x)+2))^(2), then g'(0) equals