A body is projected with a veocity of `40 ms^(-1)`. After `2 s` it fcrosses a vertical pole of height ` 20 .4 m` Find the angle of projection and horizontal range of projectile. (g = 9.8 ms^(-2)`.

A paricle is projected with a velocity of 40ms_-1 . After two seconds, it crosses a vertical pole of height 20.4m. Calculate the angle of projection.

A body is projected with a velocity 30 ms^(-1) at an angle of 30^@ with the vertical. Find (i) the maximum height (ii) time of flight and (iii) the horizontal range of the projectile. Take g=10 m//s^@ .

A body is projected with a velocity of 30 ms^(-1) at an angle of 30^(@) with the vertical. Find the maximum height, time of flight and the horizontal range.

A stone is projected horizontally with a velocity 9.8 ms^(-1) from a tower of height 100m. Its velocity one second after projection is

If the maximum vertical height and horizontal ranges of a projectile are same, the angle of projection will be