A particle is projected with velocity `2 sqrt(gh)` so that it just clears two walls of equal height h which are at a distance 2h from each other. Show that the time of passing between the walls is `2 sqrt(h//g)`.

A particle is projected with velocity 2(sqrt(gh)) , so that it just clears two walls of equal height h which are at a distance of 2h form each other. Show that the time of passing between the walls is 2 (sqrt (h/g)). [Hint : First find velocity at height h. Treat it as initial velocity and 2h as the range. ]

A particle is projected with velocity 2 sqrt((gh)) so that it just clears two walls of equal height h which are at a distance of 2h from each other. Prove that the time of flight between two walls is 2 sqrt((h/g))

A particle is projected with velocity 2 sqrt(gh) so that it just clear two walls of equal height h , which are at a distance of 2h from each other . What is the tiime interval of passing between the two walls ?

A particle is projected with velocity 2sqrt(gh) and at an angle 60^@ to the horizontal so that it just clears two walls of equal height 'h' which are at a distance 2h from each other. The time taken by the particle to travel between these two walls

A particle is projected with velocity 2 sqrt(gh) and at an agnle 60^(@) to the horizontal so that it just clears two walls of equal height h which are at a distance 2h from each other. The time taken by the particle to travel between these two wall is