The expression for potential gradent of potentiometer wire in terms of specific resistance p of the wire area of its cross -section A and current `I` flowing wire is……..

The specific resistance per unit area of cross section of a wire is equivalent to –

Calculate the potential gradient of a potentiometer wire of length 5 m ,if resistance of the wire is 5 Omega and current of 1.2 mA flows through it.

How does the resistance of a wire vary with its area of cross-section? Explain.

If the current in the primary circuit of a potentiometer wire is 0.2A, specific resistance of the material of wire 40xx10^(-8)Omega m and area of cross-section of wire is 8xx10^(-7)m^2 . The potential gradient will be

The current in the primary circuit of a potentiometer wire is 0.5 A. Specific resistance of wire is 4 xx 10^(-7) Omega m and area of cross section of wire is 8 xx 10^(-6) m^(2) . The potential gradient on the wire would be

Resistivity of the mateial of potentiometer wire is (rho) and area of its uniform cross section is A, Hence potential gradient on the wire is = ..... .